Auto power cut off timer circuit

An automatic timer switch turns OFF a load itself after a fixed period of time. The circuit will be useful for various devices which we forget to turn OFF such as light, alarm, indicator circuits, etc.

The circuit consists of a monostable multivibrator using a 555 IC. The monostable circuit has a one shot pulse output for a single triggering pulse. When we power the circuit, it triggers automatically and remains in the ON state for a preset time duration.

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The circuit can obtain a maximum ON time of 27.5 minutes. The time period can be adjusted by varying the potentiometer R1. Measure the adjusted resistance of the potentiometer and substitute the value in the below equation.

ON Time period = 1.1 R C (Here in the circuit R=R1, C=C2).

To turn off the Load manually, just open the supply switch. To restart the load after the ON period, just turn OFF the switch and then ON again. As the capacitor C3 at trigger pin requires a discharge time of very short period, the restart may require a small time interval between OFF and ON of the supply.

The output of the circuit drives an SPST relay through a transistor. The load should have connected in series through the Common and Normally open terminals of the relay. That is one of the terminals (Com or NO) connects with the supply line and other to the load.

Components required

IC1 – NE555

Resistor – R1 – 1M pot, R2 – 10k

Capacitor – C1 – 100uf, C2 – 1500nf, C3 – 33pf, C4 – 100nf

Transistor – Q1 – BC547

Diode – D1,D2,D3,D4,D5 – 1N4007

Relay – SPST 12V, 200ohms

Transformer – T1- 230v / 12V

Switch – SPST

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