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If a series circuit has three loads, each with a resistance of 6 olms, and the power source provides 120V, what is the current flowing through each of the loads? Show your calculations.
Current I = V/R
Total resistance R = R1+R2+R3
If R=6ohms, R total = 6+6+6 = 18ohms
Current I = 120/18 = 6.66A
If 3 ohms resistor it is 120/12 = 10A